T1=++t It is because the return type of operator function is void.
Algoritma pemrograman c++ code#
This program is incomplete in sense that, you cannot use code like: And, it is the job of the programmer to use operator overloading properly and in consistent manner.Īgain, the above example is increase count by 1 is not complete. Instead of making code readable this makes code obscure and confusing. If the code below was used instead, then the value of count will be decreased by 100 if ++ operates on object.īut, it does not make any sense to decrease count by 100 when ++ operator is used. But, the value is increased by 1 because, we have used the code: In above example, you have seen ++ operator operates on object to increase the value of count by 1. *(member selection through pointer to function) and ?:(ternary operator).įollowing best practice while using operator overloadingOperator overloading allows programmer to define operator the way they want but, there is a pitfall if operator overloading is not used properly. The operators that cannot be overloaded in C++ are ::(scope resolution).
Because these two operators are already overloaded in C++ library. There are two operators assignment operator(=) and address operator(&) which does not need to be overloaded.Operator overloading only allows to redefine the meaning of operator for user-defined types. Operator overloading cannot be used to change the way operator works on built-in types.Things to remember while using Operator overloading in C++ language This function will increase the value of count by 1. In this program, a operator function void operator ++ () is defined(inside class temp), which is invoked when ++ operator operates on the object of type temp.